A Room Whose Area Is78ft2202fhas A Length That Is4feet Longer Than The Width. What Arethe Dimensions

A room whose area is 78 ft2 has a length that is 4 feet longer than the width. What are   the dimensions   of the room? 

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Area of the room = 78 ft².

let the width of the room be x ft.

therefore, the length = (x + 4) ft.

according to problem,

x × (x + 4) = 78 ft².

x² + 4x = 78

x² + 4x – 70 = 0

solving equation for x

x = \frac{ - b \sqrt{b^{2} - 4ac} }{2a} \: and \: x = \frac{ - b \sqrt{b^{2} - 4ac} }{2a}

x = \frac{ - 4 \sqrt{(4)^{2} - 4 \times 1 \times ( - 78) } }{2a}

x = \frac{ - 4 + 18.11}{2}

x = 7.05 (apx.)

therefore width = 7.05 ft

and length = 7.05 + 4 = 11.05 ft

and

x = \frac{ - b \sqrt{b^{2} - 4ac} }{2a}, \: here \: x \: will \: come \: as \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ negative \: value \: which \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: is \: not \: possible

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✎sheyssssssssss


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