What Is The Area Of The Rectangle Whose Length Is (X+5) And Width (X-5)?

What is the area of the rectangle whose length is (x+5) and width (x-5)?

Answer:

x^{2} - 25 units^{2}

Step-by-step explanation:

A = lw

A = (x + 5)(x - 5)

Apply sum and difference of two squares

A = x^{2} - 25 units^{2}


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